
A Celsius thermometer and a Fahrenheit thermometer are put in a hot bath. The reading on Fahrenheit thermometer is just 3 times the reading on Celsius thermometer. The temperature of the hot bath is
A) ${26.67^ \circ }\,C$
B) ${36.67^ \circ }\,C$
C) ${46.67^ \circ }\,C$
D) ${56.67^ \circ }\,C$
Answer
180k+ views
Hint:- The above given problem can be solved using the formula that is derived for the relationship between the Celsius thermometer and the Fahrenheit thermometer of the hot bath where the Fahrenheit thermometer is just 3 times the reading on Celsius thermometer.
Useful formula:
The formula for the relationship between Celsius and Fahrenheit;
$\dfrac{{F - 32}}{{180}} = \dfrac{C}{{100}}$
Where, $F$ denotes the value of Fahrenheit in the Fahrenheit scale, $C$ denotes the value of Celsius in the Celsius scale.
Complete step by step solution:
The data given in the problem is;
Reading on Fahrenheit thermometer is just 3 times the reading on Celsius thermometer, that is;
$F = 3C$
Therefore, the relationship between Celsius and Fahrenheit;
$\dfrac{{F - 32}}{{180}} = \dfrac{C}{{100}}$
$
\dfrac{{3C - 32}}{{100}} = \dfrac{C}{{100}} \\
C = \dfrac{{80}}{3} \\
$
On simplifying we get;
$C = {26.67^ \circ }\,C$.
Therefore, the temperature of the hot bath according to the Celsius thermometer is $C = {26.67^ \circ }\,C$.
Hence the option (A), $C = {26.67^ \circ }\,C$ is the correct answer.
Note: Since in the problem it is only asked to find the temperature of the water bath Celsius thermometer that in Celsius, we didn’t calculate the temperature of the water bath in Fahrenheit thermometer.
Useful formula:
The formula for the relationship between Celsius and Fahrenheit;
$\dfrac{{F - 32}}{{180}} = \dfrac{C}{{100}}$
Where, $F$ denotes the value of Fahrenheit in the Fahrenheit scale, $C$ denotes the value of Celsius in the Celsius scale.
Complete step by step solution:
The data given in the problem is;
Reading on Fahrenheit thermometer is just 3 times the reading on Celsius thermometer, that is;
$F = 3C$
Therefore, the relationship between Celsius and Fahrenheit;
$\dfrac{{F - 32}}{{180}} = \dfrac{C}{{100}}$
$
\dfrac{{3C - 32}}{{100}} = \dfrac{C}{{100}} \\
C = \dfrac{{80}}{3} \\
$
On simplifying we get;
$C = {26.67^ \circ }\,C$.
Therefore, the temperature of the hot bath according to the Celsius thermometer is $C = {26.67^ \circ }\,C$.
Hence the option (A), $C = {26.67^ \circ }\,C$ is the correct answer.
Note: Since in the problem it is only asked to find the temperature of the water bath Celsius thermometer that in Celsius, we didn’t calculate the temperature of the water bath in Fahrenheit thermometer.
Recently Updated Pages
Degree of Dissociation Important Concepts and Tips for JEE

Learn Conversion of Galvanometer into Ammeter and Voltmeter for JEE Main

JEE Main Chemistry Question Paper PDF Download with Answer Key

Electric Field Due To Uniformly Charged Ring - JEE Main 2025

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

What is Hybridisation in Chemistry?

Other Pages
NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units and Measurements - 2025-26

NCERT Solutions For Class 11 Physics Chapter 3 Motion In A Plane - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26
