
Relation among mean, median and mode is:
A. Mode \[ = \]3Median \[ + \]2Mean
B. Mode \[ = \]3Median \[ - \]2Mean
C. Mode \[ = \]3Mean \[ + \]2Median
D. Mode \[ = \]3Mean\[ - \]2Median
Answer
516.6k+ views
Hint: Use the general empirical relationship between the mean, median and mode of a skewed distribution to calculate the relation between mean, median and mode in terms of mode.
* For a skewed distribution we have the empirical relationship between mean, median and mode as
Mean \[ - \] Mode \[ = \]3(Mean \[ - \] Median)
Complete step-by-step solution:
We are given the empirical relationship between mean, median and mode as
Mean \[ - \] Mode \[ = \]3(Mean \[ - \] Median)
If we multiply the constant value in right hand side of the equation to each term inside the bracket, we have
\[ \Rightarrow \]Mean \[ - \] Mode \[ = \]3Mean \[ - \] 3Median
Bring all terms except Mode to right hand side of the equation
\[ \Rightarrow \]\[ - \] Mode \[ = \]3Mean \[ - \] 3Median\[ - \]Mean
Pair the same terms together in a bracket
\[ \Rightarrow \]\[ - \] Mode \[ = \](3Mean \[ - \] Mean)\[ - \]3Median
Calculate the sum or difference of terms in bracket in right hand side of the equation
\[ \Rightarrow \]\[ - \] Mode \[ = \]2Mean \[ - \] 3Median
Multiply both sides of the equation by -1
\[ \Rightarrow \]\[ - 1 \times - \] Mode \[ = - 1 \times \](2Mean \[ - \] 3Median)
Multiply terms outside the bracket to terms inside the bracket in right hand side of the equation
\[ \Rightarrow \]\[ - 1 \times - \] Mode \[ = - 1 \times 2\]Mean \[ - 1 \times - 3\]Median
Use the concept that multiplication of two negative signs gives a positive sign as their product.
\[ \Rightarrow \]Mode \[ = \] 3Median \[ - \] 2Mean
\[\therefore \]Relation between mean, median and mode is Mode \[ = \] 3Median \[ - \] 2Mean
\[\therefore \]Correct option is B.
Note: Mean is nothing but the sum of observations divided by the total number of observations. Median is the middle most element of a sorted sequence. Mode is the number which is repeated the most number of times in a given sequence.
* For a skewed distribution we have the empirical relationship between mean, median and mode as
Mean \[ - \] Mode \[ = \]3(Mean \[ - \] Median)
Complete step-by-step solution:
We are given the empirical relationship between mean, median and mode as
Mean \[ - \] Mode \[ = \]3(Mean \[ - \] Median)
If we multiply the constant value in right hand side of the equation to each term inside the bracket, we have
\[ \Rightarrow \]Mean \[ - \] Mode \[ = \]3Mean \[ - \] 3Median
Bring all terms except Mode to right hand side of the equation
\[ \Rightarrow \]\[ - \] Mode \[ = \]3Mean \[ - \] 3Median\[ - \]Mean
Pair the same terms together in a bracket
\[ \Rightarrow \]\[ - \] Mode \[ = \](3Mean \[ - \] Mean)\[ - \]3Median
Calculate the sum or difference of terms in bracket in right hand side of the equation
\[ \Rightarrow \]\[ - \] Mode \[ = \]2Mean \[ - \] 3Median
Multiply both sides of the equation by -1
\[ \Rightarrow \]\[ - 1 \times - \] Mode \[ = - 1 \times \](2Mean \[ - \] 3Median)
Multiply terms outside the bracket to terms inside the bracket in right hand side of the equation
\[ \Rightarrow \]\[ - 1 \times - \] Mode \[ = - 1 \times 2\]Mean \[ - 1 \times - 3\]Median
Use the concept that multiplication of two negative signs gives a positive sign as their product.
\[ \Rightarrow \]Mode \[ = \] 3Median \[ - \] 2Mean
\[\therefore \]Relation between mean, median and mode is Mode \[ = \] 3Median \[ - \] 2Mean
\[\therefore \]Correct option is B.
Note: Mean is nothing but the sum of observations divided by the total number of observations. Median is the middle most element of a sorted sequence. Mode is the number which is repeated the most number of times in a given sequence.
Recently Updated Pages
Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is the opposite of entropy class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE
